Proof that [x + y] ≥ [x] + [y]

Since \([x] \le x\) and \([y] \le y\). Adding these two:

$$ [x] + [y] \le x+y $$

This means:

$$ [[x] + [y]] \le [x+y] $$

Since \([[x] + [y]] = [x] + [y]\):

$$ [x] + [y] \le [x+y] $$

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