[x + n] = [x] + n where n ∈ Z

By definition, \([x+n]\) is the greatest integer less than or equal to \(x+n\):

$$ [x+n] \le x+n \lt [x+n]+1 $$

By definition, we also know:

$$ [x] \le x \lt [x]+1 $$

We can add \(n\):

$$ [x] + n \le x + n \lt [x]+n+1 $$

This shows that \([x]+n\) is also the greatest integer less than or equal to \(x+n\).

If both \([x]+n\) and \([x+n]\) are the greatest integers below \(x+n\), then \([x]+n = [x+n]\).

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